x^2-15x+53=0

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Solution for x^2-15x+53=0 equation: 



x^2-15x+53=0

a = 1; b = -15; c = +53;
Δ = b2-4ac
Δ = -152-4·1·53
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{13}}{2*1}=\frac{15-\sqrt{13}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{13}}{2*1}=\frac{15+\sqrt{13}}{2}
$

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